how fast would she have to be running for her race to appear to her to be only 91 yd long? give your answer in terms of c.

The rate at which an object's location changes in any direction is what is known as speed. The distance traveled in relation to the time it took to travel that distance is how speed is defined.
The Speed just has a direction and does not have magnitude hence, speed is a scalar quantity.

Given:

Race length=100M=L

she has to appear=91yd

to find this we need to

[tex]L_{o}[/tex]=100M

1 yard =0.9144 meter

hence, L=91yard*0.9144/1

[tex]L_{o[/tex]=83.2104m

now do as follows:

L=[tex]L_{o}[/tex][tex]\sqrt{1-\frac{v^{2} }{c^{2} } }[/tex]

Solving the equation we get

v=2*9.88^8*[tex]\sqrt{\frac{83.21^{2} }{100^{2} } }[/tex]

v=1.81*10^8m/s

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The complete question is:

How fast would she have to be running for her 100m race to appear to be only 91 yard long? give your answer in terms of c.