If the initial population of a town is 100,231 and it grows with a doubling time of 98 years, the population after 31 years is 124803
The initial population of the town = 100231 people
The doubling time = 98 years
We have to find the population in 31 year
The exponential function will be
f(t) = fo(2)^(t/98)
f(t) is the population of the town in t years
fo is the population of the town in t = 0 years
t is the number of years
2 because it doubling time
The value of t = 31 years
Substitute the values in the function
f(31) = 100231×(2)^(31/98)
Do the arithmetic operations
f(31) = 100231 × 1.245
f(31) = 124803.23
f(31) ≈ 124803
Therefore, the population after 31 years is 124803
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