The molar mass of caf2 is 78.075 g/mol is 4.14 x 10^ -11.
CaF2 (s) <----> Ca2+ (aq) + 2F- (aq)
At equilibrium [Ca2+] = S , [F-] = 2S , where S is amount of CaF2 dissolved i.e solubility.
The molar mass of a chemical compound is determined by dividing its mass by the quantity of that compound, expressed as the number of moles in the sample, measured in moles. The molar mass of a material is a bulk attribute rather than a molecular one.
given S = 1.7 x 10^ -2 g/L = 0.017 g/L
we can convert g/L to mol/L by dividing S with Molar mass of CaF2
S in mol / L = (S in g/L) / ( CaF2 molar mass) = ( 0.017g/L) / ( 78.07g/mol) = 0.000218 mol /L
[F-] = 2S = 2 x ( 0.000218) = 0.000436 mol/L
now Ksp = [Ca2+] [F-]^2
= ( 0.000218 ) (0.000436 )^2
= 4.14 x 10^ -11
To learn more about solubility visit:https://brainly.com/question/29661360
#SPJ4
