Given the points (-3,-5) and (1,-3), we can derive the equation of the line using the formula:
[tex]\begin{gathered} \frac{y-y_1}{x-x_1}\text{ = }\frac{y_2-y_1}{x_2-x_1} \\ by\text{ substituting, we have} \\ \frac{y\text{ - (-5)}}{x\text{ - (-3)}}\text{ =}\frac{-3\text{ - (-5)}}{1\text{ - (-3)}} \\ \frac{y\text{ + 5}}{x\text{ + 3}}\text{ = }\frac{2}{4} \\ 4(y\text{ + 5) = 2(x + 3)} \\ 4y\text{ - 2x + 14 = 0} \\ y\text{ = }\frac{1}{2}x\text{ }-\frac{7}{2} \end{gathered}[/tex]
This corresponds to option A
