The equation to obtain the vertical distance cobered by the object is,
[tex]h=ut+\frac{1}{2}gt^2[/tex]The acceleration due to gravity on saturn is 0.066 m/s2.
Plug in the known values,
[tex]\begin{gathered} 10\text{ m=(0 m/s)t+}\frac{1}{2}(0.066m/s^2)t^2 \\ t^2=\frac{2(10\text{ m)}}{0.066m/s^2} \\ t=\sqrt[]{303.03s^2} \\ \approx17.4\text{ s} \end{gathered}[/tex]Thus, the time taken by object to fall is 17.4 s.
