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If P(x) = 245000...
245000 = 75000(x - 1940)^(1/3)
x ≈ 1975
If P(x) = 245000...
245000 = 75000(x - 1940)^(1/3)
x ≈ 1975
Answer: B. 1975
Step-by-step explanation:
Given: The model of population of a certain city between the years 1965 and 1995 by the radical function
[tex]P(x)=75000\sqrt[3]{x-1940}[/tex]
To find the x year at which population is 245,000, put this in equation we get
[tex]245000=75000\sqrt[3]{x-1940}\\\\\Rightarrow\frac{245000}{17000}=\sqrt[3]{x-1940}\\\\\Rightarrow3.266=\sqrt[3]{x-1940}\\\\\Rightarrow\ x-1940=(3.266)^3..........\text{[by taking cube on both sides]}\\\\\Rightarrow\ x-1940=34.8587\\\\\Rightarrow\ x=1940+34.8587\\\\\Rightarrow\ x=1974.8587\approx1975[/tex]
Hence, at year 1975 the population of the city is 245,000.