Respuesta :

[tex]\bf \textit{Double Angle Identities} \\ \quad \\ sin(2\alpha)=2sin(\alpha)cos(\alpha) \\ \quad \\ \boxed{cos(2\alpha)= \begin{cases} cos^2(\alpha)-sin^2(\alpha)\\ 1-2sin^2(\alpha)\\ 2cos^2(\alpha)-1 \end{cases}} \\ \quad \\ tan(2\alpha)=\cfrac{2tan(\alpha)}{1-tan^2(\alpha)}[/tex]