cgarciaest
cgarciaest cgarciaest
  • 14-02-2017
  • Mathematics
contestada

Using the graph of f(x)=log2^X below, approximate the value of y in the equation 2^2y=3 y=4.01. y=.79. y=1.58. y=0.47

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selbyy19
selbyy19 selbyy19
  • 14-02-2017
the answer would be y=.79
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