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five charges are placed in a closed box. each charge (except the first) has a magnitude which is twice that of the previous one placed in the box. all charges have the same sign and (after all the charges have been placed in the box) the net electric flux through the box is 7 × 107 n · m 2 /c. what is the magni

Respuesta :

The magnitude of the charge is  q = 13.423 µC.

What is point charge?

If the magnitude of an electric charge for a body is very small compared to the distance between them, they are referred to as point charges. As a result, the charge is thought to be concentrated at that location.

Let the first charge be q.

So

q1 = q

q2 = 2q

q3 = 4q

q4 = 8q

q5 = 16q

Total charge Q = q1 + q2 + q3 + q4 + q5 = 31q

Flux f = 4.7 × 10^7 N · m2/C

According to gauss law

                 Flux f = Q/(permittivity of free space)

            4.7 × 10^7 = 31q/(8.854*10^-12)

                         q = 1.3423*10^-5

                            = 13.423*10^-6 C

                            = 13.423 µC

The smallest possible charge q = 13.423 µC  

to learn more about point charge go to -

https://brainly.com/question/17950445

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