The correct answer is 48.36 g .
A mole of any material is equal to 6.023 x 1023, or Avogadro's number. Additionally, it is employed to express concentrations in terms of moles per litre or molecular weight.
Number of moles of O = (Mass of O / Molar mass of O) = ( 25.7 g / 15.999 g/mol) = 1.6 mol
3 mol of O combine with 2 mol of Fe (iron) to form Fe2O3 . Or, 1 mol of O combines with (2/3) mol of Fe.
Therefore, 1.6 mol of O combine with = (2/3) × 1.3 = 0.866 mol of Fe
Mass of Fe (iron) = (Number of moles of Fe) × (Molar mass of Fe) = (0.866 mol) × (55.845 g/mol) = 48.36 g
Hence, the amount of iron required = 48.36 g
To learn more about Avogadro's number refer the link:
https://brainly.com/question/20091306
#SPJ9
