a soccer ball is kicked at an angle of 64° to the horizontal with an initial speed of 15 m/s. assume for the moment that we can neglect air resistance. (a) for how much time is the ball in the air?

Respuesta :

Time taken by the soccer ball in the air when we neglect the air resistance is 2.75s

projectile motion - It is the motion of an object which projected into the air  and moving under the gravity.

a soccer ball is kicked at an angle of 64° to the horizontal

initial speed = 15 m/s

Initial velocity in vertical direction is given as

[tex]V_{v} = V_{0}sin \theta[/tex]

[tex]V_{v} = 15sin(64)[/tex]

[tex]V_{v}[/tex] = 15× 0.8987

    = 13.48m/s

time taken to reach the maximum height is given by

T =[tex]V_{v}[/tex] /g

where

[tex]V_{v}[/tex]  is the velocity

g is the gravity

Ball comes downward with the same speed

then that time period is given by.

2[tex]V_{v}[/tex] /g

= 2× 13.48 /9.8

T = 2.75s

Time taken by the soccer ball in the air when we neglect the air resistance is 2.75s

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