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A dart is thrown horizontally at a speed of 12 m/s at the bull's-eye of a dartboard 2.7 m away. How far below the intended target does the dart hit (in m)?

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onyebuchinnaji

The distance below the intended target the dart hit is 0.26 m.

Time of motion of the dart

The time taken for the  dart to fall is calculated as follows;

X = Vxt

where;

  • X is the horizontal displacement
  • Vx is the horizontal speed
  • t is time of motion

t = X/Vx

t = 2.7/12

t = 0.23 seconds

Height of fall of the dart

h = vt + ¹/₂gt²

where;

  • v is initial vertical velocity = 0

h = ¹/₂gt²

h = ¹/₂(9.8)(0.23²)

h = 0.26 m

Learn more about height of fall here: https://brainly.com/question/1850420

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