The value of the expression (4x^6) * 3y^5/6x^3y^3 is 2x^3y^2
How to evaluate the expression?
The expression is given as
(4x^6) * 3y^5/6x^3y^3
Divide 3 and 6 by 3
So, we have
(4x^6) * 3y^5/6x^3y^3 = (4x^6) * y^5/2x^3y^3
Apply the law of indices to the exponents
(4x^6) * 3y^5/6x^3y^3 = (4x^6) * y^2/2x^3
Remove the bracket
(4x^6) * 3y^5/6x^3y^3 = 4x^6 * y^2/2x^3
Divide 4 and 2 by 2
So, we have
(4x^6) * 3y^5/6x^3y^3 = 2x^6 * y^2/x^3
Apply the law of indices to the exponents
(4x^6) * 3y^5/6x^3y^3 = 2x^3y^2
Hence, the value of the expression (4x^6) * 3y^5/6x^3y^3 is 2x^3y^2
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