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If 0.459 g of an unknown sugar is dissolved in 100.0 mL of water its osmotic pressure is found to be 0.0824 atm.. If the temperature of the solution was 298 K, what is the molar mass of the sugar (in g/mol)? Give your answer to three sig figs

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mahima6824soni

The molar mass of the sugar (in g/mol) is  \M = 3.0067.

What is molar mass?

"Molar mass of many compounds can be calculated by dividing the mass of the compound by the number of moles of the compound."

Given, that the mass of unknown sugar= 0.459 g

Volume of water =  100.0 mL

Osmotic pressure to be 0.0824 atm

The temperature of the solution = 298 K

Calculating the moles

PV = nRt

R =  8.314, constant

0.0824 X 100.0 = n x 8.314 x  298

8.24 = n x 2477.57

n = 300.67

Now, calculating the molar mass

Molar mass = n  / V

300.67 /  100.0

M = 3.0067

Thus, the molar mass of the sugar is 3.0067

To learn more about molar mass, refer to the below link:

https://brainly.com/question/12127540

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