Answer:
○ a) [tex]\displaystyle 9\:m.[/tex]
Step-by-step explanation:
[tex]\displaystyle \frac{15}{x} = sec\:53 \hookrightarrow xsec\:53 = 15 \hookrightarrow \frac{15}{sec\:53} = x \hookrightarrow 9,0272253473... = x \\ \\ 9 ≈ x[/tex]
OR
[tex]\displaystyle \frac{x}{15} = cos\:53 \hookrightarrow 15cos\:53 = x \hookrightarrow 9,0272253473... = x \\ \\ 9 ≈ x[/tex]
Information on trigonometric ratios
[tex]\displaystyle \frac{OPPOCITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOCITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOCITE} = csc\:θ \\ \frac{ADJACENT}{OPPOCITE} = cot\:θ[/tex]
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