Answer:
[tex]the \: answer \: is \: c \: = - \frac{ \sqrt{14} }{5} [/tex]
Step-by-step explanation:
[tex] \sin^{2}0 + ( \frac{ \sqrt{11} }{5} ) ^{2} = 1( \sin^{2}0 + \cos^{2} 0 = 1)[/tex]
[tex] { \sin }^{2}0 + \frac{11}{25} = 1 \\ { \sin }^{2}0 = \frac{14}{25} [/tex]
[tex] \sin0_{1} = - \frac{ \sqrt{14}}{5} while \sin0_{2} = \frac{ \sqrt{14} }{5} [/tex]
- Therfore theta is QI
- Therfore sin theta >0
- [tex]therefore \: \sin0 = \frac{ \sqrt{14} }{5} [/tex]
