A laser beam is incident on the surface of a block of ice at an angle of 38.0° with respect to the normal (a line perpendicular to the surface at the spot where the ray hits the block).

A fraction of the light is reflected and the rest refracted. What is the angle (in degrees) between the reflected and refracted beams?

_______°

Respuesta :

The angle that exists between the light that is reflected and the ray that is refracted is  mathematically given as

=122.2°

What is Snell's Law?

When talking about light or other waves that have to cross a border between two isotropic mediums like water, glass, or air, Snell's law is the formula used to define the connection between the angles of incidence and refraction.

Use the following Snell's law equation.

[tex]$n_{1} \sin \theta_{i}=n_{2} \sin \theta$[/tex]

Rearrange the above equation for the refractive angle of the refracted ray in zircon.

[tex]$\begin{aligned}\sin \theta_{r} &=\frac{n_{1} \sin \theta_{i}}{n_{2}} \\\theta_{r} &=\sin ^{-1}\left(\frac{n_{1} \sin \theta_{i}}{n_{2}}\right) \\&=\sin ^{-1}\left(\frac{(1) \sin 39^{\circ}}{1.95}\right) \\&=\sin ^{-1}\left(\frac{(1)(0.629320)}{1.95}\right) \\&=18.83^{\circ}\end{aligned}$[/tex]

The angle between the part of the reflected ray and the refracted beams is,

[tex]$\begin{aligned}\phi &=180^{\circ}-\left(\theta_{i}+\theta_{r}\right) \\&=180^{\circ}-\left(39^{\circ}+18.83^{\circ}\right) \\&=122.2^{\circ}\end{aligned}$[/tex]

In conclusion, the angle that exists between the light that is reflected and the ray that is refracted is

=122.2°

Read more about Snell's law

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