A simple pendulum of length 1.5m has a bob of mass of 2.0kg, then the period for the small oscillations would be 2.456 s.
It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.
The frequency of a pendulum is the reciprocal of the time period can be given by the following relation,
f = 1/T
As given in the problem A simple pendulum of length 1.5m has a bob of mass of 2.0kg.
The formula for the time period for the pendulum,
T = 2π√L/g
=2π√1.5/9.81
=2.456 s
Thus, the period for the small oscillations would be 2.456 s.
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