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102 The battery in the circuit diagram below has negligible internal resistance. The resistance of resistor R is unknown. When the switch is closed, the voltmeter reads 15 V and the ammeter A, reads 1 A. Calculate the: 10.2.1 Cument in ammeter A 6Q V 15V 1 A A1 6Q 12 Q R ​

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Eduard22sly

The resistance of the resistor given that the ammeter reads 1 A when the switch is closed is 15 V / 1 A

Ohm's law

This law states that the current flowing through a metallic conductor is directly proportional to the voltage provided every physical properties remains constant. It can be written mathematically as:

V = IR

Where

  • V is the voltage
  • I is the current
  • R is the resistor

How to determine the resistor

From the question given, the following data were obtained:

  • Voltage (V) = 15 V
  • Current (I) = 1 A
  • Resistor (R) =?

We can determine the resistance of the resistor as follow:

V = IR

15 V = 1 A × R

Divide both sides by 1 A

R = 15 V / 1 A

Thus, the resistance of the resistor is 15 V / 1 A

Learn more about Ohm's law:

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