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If 21.9 grams of an aqueous solution of zinc sulfate, ln(S*O_{4}) , contains 4.44 grams of zinc sulfate, what is the percentage by mass of zinc sulfate in the solution?

If 219 grams of an aqueous solution of zinc sulfate lnSO4 contains 444 grams of zinc sulfate what is the percentage by mass of zinc sulfate in the solution class=

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Answer:

20.27%.

Explanation:

Divide the mass of zinc sulfate (4.44g)  by the total mass of the solution (21.9) and multiply for 100 to get the percentage:

[tex]\frac{4.44g}{21.9g}*100= 20.27[/tex]%.

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