mlbjohny92 mlbjohny92

15-07-2022
Physics

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An ideal gas in an isentropic process has an initial pressure of 200 kPa and relative pressure is 3.482; the final pressure is now 320 kPa, find the relative pressure at this state. round to the nearest 3 decimal places

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onyebuchinnaji onyebuchinnaji

18-07-2022

The relative pressure at this state is determined as 0.455.

Initial pressure of the ideal gas

The pressure of the ideal gas given rise to the relative pressure is calculated as follows;

R.P = P2/P1

P2 = P1(R.P)

P2 = 200 kPa x (3.482)

P2 = 696.4 kPa

New relative pressure

R.P = (P3)/(P2)

R.P = (320)/(696.4)

R.P = 0.455

Thus, the relative pressure at this state is determined as 0.455.

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