The value of sec(V) is 5/3
How to solve the trigonometry expression?
The tangent is given as:
tan(V) = 4/3
To solve for sec(V), we use the following identity
sec^2(V) = tan^2(V) + 1
So, we have:
sec^2(V) = (4/3)^2 + 1
This gives
sec^2(V) = 16/9 + 1
Evaluate the sum
sec^2(V) = 25/9
Take the square root
sec(V) = 5/3
Hence, the value of sec(V) is 5/3
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