The Area of triangle is A= 58.02 (ft)^2
According to statement
Let
B is the measure of the vertex angle of the isosceles triangle ABC
A and C is the two congruent sides of the isosceles triangle ABC
we know that
The area of a triangle applying the law of sines is equal to the
A= 1/2 *AC *SinB
we have
A=C= 17.91 ft
And
B= 21.21
Substitute these values in the formula
A= 1/2* 17.91* 17.91 * Sin(21.21)
A= 58.02 (ft)^2
So, the Area of triangle is A= 58.02 (ft)^2
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