The moles of ZnCl₂ in 1.5 L of the 0.2 M solution is 0.3 moles.
The moles of ZnCl₂ is present in in 1.5 L of a 0.2 M solution is calculated using the formula below:
Moles of ZnCl₂ = 1.5 x 0.2
Moles of ZnCl₂ = 0.3 moles
In conclusion, the moles of ZnCl₂ in the given volume of solution is determined from the molarity of the solution and the volume of solution.
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