[tex]\large\boxed{\frac{1}{1369}}[/tex]
We'll assume that there is an equal probability of any position on the wheel, so a [tex]\frac{1}{37}[/tex] chance for any given number.
We must take the probability of getting a 27, then the probability of getting a 15, and multiply them together to find the chances that they both happen in a row.
[tex]\frac{1}{37}\cdot\frac{1}{37}=\boxed{\frac{1}{1369}}[/tex]
