After 24 hours, 35.4% of the initial dosage remains on the body.
The exponential decay is written as:
[tex]f(x) = A*e^{-k*x}[/tex]
Where A is the initial value, in this case 2.8mg.
k is the constant of decay, given by the logarithm of 2 over the half life, in this case, is:
[tex]k = ln(2)/16h[/tex]
Replacing all that in the above formula, and evaluating in x = 24 hours we get:
[tex]f(24h) = 2.8mg*e^{-24h*ln(2)/16h} = 0.9899 mg[/tex]
The percentage of the initial dosage that remains is:
[tex]P = \frac{0.9899mg}{2.8mg}*100\% = 35.4\%[/tex]
If you want to learn more about exponential decays:
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