Respuesta :
We cannot express the function [tex]x^{2} -sin(x+y)=1[/tex] in y=f(x) form it has an implicit function.
Given function [tex]x^{2} -sin(x+y)=1[/tex] and dy/dx=2x sec(x+y)-1
A relation is said to be an implicit solution of a differential equation involving x,y and derivatives of y with respect to x if defined explicit solution. In other words the function which cannot be written as y=f(x).
Function is a relationship between two or more variables which have one value for each value of x.
We have to first differentiate the function with respect to x.
[tex]x^{2} -sin(x+y)=1[/tex]
2x-cos(x+y)(1+dy/dx)=0
2x-cos(x+y)+cos(x+y)dy/dx=0
cos(x+y) dy/dx=cos(x+y)-2x
dy/dx={cos(x+y)-2x}/cos(x+y)
dy/dx=cos(x+y)/cos(x+y)-2x/cos(x+y)
dy/dx=1-2x cos(x+y)
The given solution is incorrect.
when we solve the function to collect the variable y in one side we cannot be able to do that.
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