The new pressure will be 7.65 atm
The problem is solved using the general gas equation:
P1V1/T1 = P2V2/T2
In this case, P1 = 3.4 atm, V1 = 1500 mL, T1 = 25 [tex]^O C[/tex], V2 = 2000 mL, and T2 = 75 [tex]^O C[/tex]
What we are looking for is P2.
Thus, P2 = P1V1T2/T1V2
= 3.4 x 1500 x 75/25 x 2000 = 382500/50000 = 7.65 atm
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