The molecular formula of the compound is C6H6
First, convert the percentages to moles
C = 92.9/12 = 7.74
H = 7.71/1 = 7.71
Thus, the empirical formula will be CH
[empirical formula]n = molecular formula
Empirical formula mass = 12 + 1 = 13
n = empirical formula mass/molar mass = 78/13 6
Thus, the molecular formula will be C6H6
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