13. A compound with a molar mass of 78.0 g/mol is found to contain 92.29%
carbon and 7.71% hydrogen, by mass. The molecular formula of the compound is
a. CH
b. C₂H3
c. C3H3
d. C5H₁
e. C6H6

Respuesta :

Oseni

The molecular formula of the compound is C6H6

Molecular formula

First, convert the percentages to moles

C = 92.9/12 = 7.74

H = 7.71/1 = 7.71

Thus, the empirical formula will be  CH

[empirical formula]n = molecular formula

Empirical formula mass = 12 + 1 = 13

n = empirical formula mass/molar mass = 78/13 6

Thus, the molecular formula will be C6H6

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