The system of equations has (d) 0 real solutions
The system of equations is given as:
y = x^2+1
y=x
Substitute y=x in y = x^2+1
x = x^2+1
This gives
x^2 - x + 1 = 0
Calculate the discriminant using:
d = b^2 - 4ac
So, we have:
d = (-1)^2 - 4 * 1 * 1
Evaluate
d = -3
Because the discriminant is negative, the equation has no real solution
Hence, the system of equations has (d) 0 real solutions
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