Respuesta :
Ly has 15 dimes, 12 nickels and 30 quarters given that he has 3 more dime than nickels and twice as many quarters than dimes and the value of these coins is $9.60. This can be obtained by giving variables to each represent the number of each coin and adding the values to equate with the total value of coins.
How many of each coin does he have?
Let number of dimes be y
Given that,
3 more dime than nickels ⇒ Number of nickel = y - 3
twice as many quarters than dimes ⇒ Number of quarters = 2y
- Value of one dime = $ 0.1
- Value of one nickel = $ 0.05
- Value of one quarter = $ 0.25
9.60 = 0.1y + 0.05(y-3) + 0.25(2y)
9.60 = 0.1y + 0.05y - 0.15 + 0.5y
9.60 = 0.1y + 0.05y - 0.15 + 0.5y
9.60 + 0.15 = 0.65y
y = 9.75/0.65 = 15
y = 15
Therefore the number of each coin,
- Number of dimes = y = 15
- Number of nickel = y - 3 =15-3 = 12
- Number of quarters = 2y =2×15 =30
Hence Ly has 15 dimes, 12 nickels and 30 quarters given that he has 3 more dime than nickels and twice as many quarters than dimes and the value of these coins is $9.60.
Learn more about solving algebraic expressions here:
brainly.com/question/17334356
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