A solid cylinder of mass (M=1 kg) and radius R=0.5 m is pivoted at its center The axis of rotation of the cylinder is horizontal. Three small particles of mass (m=0.1 kg) are mounted along its surface as shown in the figure. The system is initially at rest.
Solid cylinders need to be cut or split into small thin rings.
Each ring consists of a thickness dr of length L.
The moments of these thin cylindrical shells should be summed to infinitesimal.
Follow the instructions given.
1st place Use the general moment of inertia equation.
dI = r2 dm
Next, proceed to the dm determination. It is usually given as follows: To get
dm = ρdV
dm, you first need to calculate DV. It is given as follows:
dV = dA L
where dA is the area of the large ring (radius: r + dr) minus the small ring (radius: r). as a result;
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