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The diagram shows the intersections of several straight roads. The avenues run parallel to each other.

First Avenue and Second Avenue are parallel. Oak goes through both streets at point A and B. Main goes diagonally down through both streets and intersects with Oak Street. The distance from First to Second on Main is 280 feet. The distance from Second to the intersection of Oak is 140 feet. The distance from Point B to the intersection of Main is 113 feet.

Amana walks along Oak from point A to B. To the nearest foot, how far does she walk?
75 ft
226 ft
307 ft
347 ft

Respuesta :

Lanuel

By applying the property of similar triangles, the distance Amana from point A to B walked is: B. 226 ft.

How to determine the distance?

By critically observing the diagram (see attachment), we can deduce that two (2) similar triangles were formed by the First Ave. and Second Ave.

By applying the property of similar triangles, the distance Amana walked is given by:

(AB + 113)/113 = (280 + 140)/140

(AB + 113)/113 = 420/140

(AB + 113)/113 = 3

AB + 113 = 3 × 113

AB + 113 = 339

AB = 339 - 113

AB = 226 ft.

Read more on similar triangles here: https://brainly.com/question/1518795

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Ver imagen Lanuel

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