The proportion of people who preferred foreign cars than domestic cars is 0.24 and the confidence interval for the population proportion of new cars over domestic cars of 98% confidence interval is (641.955,642.045).
Given sample size of 2676 and number of people preferred foreign cars than domestic cars is 642.
We have to calculate the proportion of people who preferred foreign cars than domestic cars and the confidence interval which shows the confidence interval of 98%.
Number of people prefer foreign cars than domestic cars=642
Sample size=2676
Proportion=642/2676
=0.2399
=0.24 (After rounding off)
Now we will find confidence interval.
X=642
n=2676
z value for the confidence interval 98% is 2.33
Confidence interval =X± z*s/[tex]\sqrt{n}[/tex]
Upper =642+2.33*1/[tex]\sqrt{2676}[/tex] (we have taken s=1)
=642+0.045
=642.045
Lower=642-2.33*1/[tex]\sqrt{2676}[/tex]
642-0.045 (putting values in formula given above)
=641.955
Hence the proportion of people preferred foreign cars than domestic cars is 0.24 and the confidence interval is (641.955,642.045).
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