1. A football is kicked with a velocity. of 20m/s at an angle of 45° with the horizontal i. Find the time taken by the ball to strike the ground ii. Find the maximum height 11. How far from the kick does it hit the ground Take gravity = 10 m/s​

Respuesta :

(a) The maximum height reached by the projectile is 10.2 m and

(b) The horizontal distance traveled by the projectile is 40.8 m.

Maximum height reached by the projectile

H = u²sin²θ/2g

H = (20²(sin(45))² / (2 x 9.8)

H = 10.2 m

Time of motion

T = (2u sinθ)/g

T = (2 x 20 x sin(45) )/(9.8)

T = 2.886 s

Horizontal distance traveled by the projectile

x = (v cos(45) x t

x = (20 x cos(45)) x 2.886

x = 40.8 m

Thus, the maximum height reached by the projectile is 10.2 m and the horizontal distance traveled by the projectile is 40.8 m.

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