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Triangle QRS is to be dilated using the rule D Subscript P, three-fourths.

Point P is the center of dilation. Triangle Q R S is shown. The length of P S is 8.

What will be the distance from the center of dilation, P, to the image S'?

2 units
4 units
6 units
8 units

Respuesta :

adioabiola

The distance from the center of dilation, P, to.the image vertice S' is; 6 units.

What is the distance from the center of dilation, P, to the image S'?

It follows from the task content that the center of dilation of the triangle QRS is point P and the length of segment PS in the pre-image is; 8 units.

Ultimately, since the dilation factor is; three-fourths, it therefore follows that the distance of point P to S' in the image is; (3/4) × 8 = 6 units.

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