The linear equation is represented by the second table as y= -2 .5 x-15 and the solution to the system of equations is (-6, 0).
First, take two point from the table and as such it will be:
P (-4, -5) and Q(-2, -10)
So the two point is used to create a straight line and as such it will be:
y - y₁ = y₂ - y₁/ x₂ - x₁ (x₁-x )
y -(-5) = [tex]\frac{-10-(-5)}{-2-(-4)}[/tex] (x -(-4))
y + 5 = [tex]\frac{-5}{2}[/tex] x +4
y + 5 = [tex]\frac{-5}{2}[/tex] x - 10
y = [tex]\frac{-5}{2}[/tex] x - 15
y= -2 .5 x-15
The linear equation is represented by the second table as y= -2 .5 x-15 and the solution to the system of equations is (-6, 0)
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