Volume round to nearest tenth

The total volume of the given figure is:
[tex]V = 311.65cm^3 + 246.97cm^3 = 558.62cm^3[/tex]
Here we have two simple shapes.
Half a sphere, and a cone.
The volume of half a sphere of radius R is:
[tex]V = \frac{2}{3}*3.14*R^3[/tex]
And here we know that R = 5.3cm, replacing that we get:
[tex]V = \frac{2}{3}*3.14*(5.3cm)^3 = 311.65cm^3[/tex]
For a cone of radius R and height H, the volume is:
[tex]V = \frac{3.14*R^2*H}{3}[/tex]
In this case, R = 5.3cm and H = 8.4cm
The volume of the cone is:
[tex]V = \frac{3.14*(5.4cm)^2*8.4cm}{3} = 246.97cm^3[/tex]
Then the total volume is:
[tex]V = 311.65cm^3 + 246.97cm^3 = 558.62cm^3[/tex]
If you want to learn more about volume:
https://brainly.com/question/1972490
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