Wan has 22 bulbs of the same shape and size in a box. The colors of and amounts of the bulbs are shown below:

6 blue bulbs
9 red bulbs
7 orange bulbs

Without looking in the box, Wan takes out a bulb at random. He then replaces the bulb and takes out another bulb from the box. What is the probability that Wan takes out an orange bulb in both draws? (5 points)

Wan has 22 bulbs of the same shape and size in a box The colors of and amounts of the bulbs are shown below 6 blue bulbs 9 red bulbs 7 orange bulbs Without look class=

Respuesta :

It would be A since there are 7 orange light bulbs out of 22 in the box and we are told that Wan put back the light bulb he took out so the denominator will not decrease from 22 so the answer would be A which is 7/22 x 7/22 = 49/484.

Hope this helps buddy

Answer: A

Step-by-step explanation:

This type of question is compound probability and it involves independent variables because the outcome of 1 event doesn't impact the probability of the next one.

the probability of taking an orange bulb is 7/22. Since he put that bulb back in the box, the probability of taking an orange bulb again, doesn't change. So the "compound probability " is 7/22x7/22= 49/484.

Answer= A

Hope this helps :)) And Brainliest would be appreciated :)