Answer:
The correct answer is: "Option [D]".
Step-by-step explanation:
Hi student, let me help you out!
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Let's use the acronym PEMDAS. With the help of this little acronym, we will not make mistakes in the Order of Operations! :)
[tex]\dag\textsf{Acronym \: PEMDAS}[/tex]
P=Parentheses,
E=Exponents,
M=Multiplication,
D=Division,
A=Addition,
S=Subtraction.
Now let's start evaluating our expression, which is [tex]\mathsf{6-(\cfrac{2}{3})^2}[/tex]
According to PEMDAS, the operation that we should perform is "E-Exponents".
Notice that we have a fraction raised to a power. When this happens, we raise both the numerator (2 in this case) and the denominator (3 in this case) to that power, which is 2. After this we obtain [tex]\mathsf{6-\cfrac{4}{9}}[/tex].
See, we raised both the numerator and the denominator to the power of 2.
Now what we should do is subtract fractions.
Note that 6 and -4/9 have unlike denominators. First, let's write 6 as a fraction: [tex]\mathrm{\cfrac{6}{1}-\cfrac{4}{9}}[/tex]. Now let's multiply the denominator and the numerator of the first fraction times 9: [tex]\mathrm{\cfrac{54}{9}-\cfrac{4}{9}}[/tex].
See, now the fractions have the same denominator. All we should do now is subtract the numerators: [tex]\mathrm{\cfrac{50}{9}}[/tex].
∴, the answer is Option D.
Hope this helped you out, ask in comments if any queries arise.
Best Wishes!
[tex]\star\bigstar\underline{\overline{\overline{\underline{\textsf{Reach \: far. Aim \: high. Dream \: big.}}}}}\bigstar\star[/tex]
[tex]\underline{\rule{300}{5}}[/tex]
Calculate 2/3, to the power of 3, therefore
[tex]\bf{\left(\dfrac{2}{3}\right)^{2}=\dfrac{2\times2}{3\times3}=\dfrac{4}{9} }[/tex]
[tex]\bf{6-\dfrac{4}{9} }[/tex]
Convert 6 to the fraction 54/9.
[tex]\bf{\dfrac{54}{9}-\dfrac{4}{9} }[/tex]
Since 54/9 and 4/9 have the same denominator, join their numerators to subtract them.
[tex]\bf{\dfrac{54-4}{9} \ \ \to \ \ \ Subtract }[/tex]
Subtract 4 from 54 to get 50.
[tex]\bf{\dfrac{50}{9} \ \ \to \ \ \ Answer }[/tex]
Therefore, the correct alternative is "D".
[tex]\red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]
