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ABCD is a quadrilateral inscribed in a circle, as shown below:

What equation can be used to solve for angle A? (1 point)
(x + 16) + (6x − 4) = 180
(x + 16) + (x) = 90
(x + 16) − (2x + 16) = 180
(x + 16) − (x) = 90

ABCD is a quadrilateral inscribed in a circle as shown below What equation can be used to solve for angle A 1 point x 16 6x 4 180 x 16 x 90 x 16 2x 16 180 x 16 class=

Respuesta :

The equation that can be used to solve for angle A is (x+16)° + (6x-4)° = 180°. The correct option is the first option- (x+16) + (6x-4) = 180

Circle Geometry

From the question, we are to determine the equation that could be used to solve for angle A

From one of the circle theorems

Opposite angles of a cyclic quadrilateral are supplementary

That is,

∠A + ∠C = 180°

∴ (x+16)° + (6x-4)° = 180°

Hence, the equation that can be used to solve for angle A is (x+16)° + (6x-4)° = 180°. The correct option is the first option- (x+16) + (6x-4) = 180

Learn more on Circle Geometry here: https://brainly.com/question/9172423

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heathermalatesta

Answer:

(x + 16) + (6x − 4) = 180

Step-by-step explanation:

When a quadrilateral is inscribed in a circle, opposite angles are supplementary, meaning they add to 180 degrees.

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