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What are the zeros of the quadratic function f(x) = 2x² + 16x - 9?
7
O x = -4 -
-√7
and x = -4 +
+√√2/2
O x=-4- 25
and x = 4 +
-
2
21
0 x = -4-√²/²
and x = -4 +
2
41
Ox=-4-
and x = -4 +
2
|~~
25
2
21
2
41
2

What are the zeros of the quadratic function fx 2x 16x 9 7 O x 4 7 and x 4 22 O x4 25 and x 4 2 21 0 x 4 and x 4 2 41 Ox4 and x 4 2 25 2 21 2 41 2 class=

Respuesta :

The zeros of the quadratic function f(x) = 2x² + 16x - 9 are given as follows:

[tex]x = -4 + \sqrt{\frac{41}{2}}, x = -4 - \sqrt{\frac{41}{2}}[/tex]

What is a quadratic function?

A quadratic function is given according to the following rule:

[tex]y = ax^2 + bx + c[/tex]

The solutions are:

[tex]x_1 = \frac{-b + \sqrt{\Delta}}{2a}[/tex]

[tex]x_2 = \frac{-b - \sqrt{\Delta}}{2a}[/tex]

In which:

[tex]\Delta = b^2 - 4ac[/tex]

In this problem, the equation is given by:

f(x) = 2x² + 16x - 9.

The coefficients are a = 2, b = 16, c = -9, hence:

[tex]\Delta = 16^2 - 4(2)(-9) = 328[/tex]

Then:

[tex]x_1 = \frac{-16 + \sqrt{328}}{2(2)} = -4 + \sqrt{\frac{41}{2}}[/tex]

[tex]x_2 = \frac{-16 - \sqrt{328}}{2(2)} = -4 - \sqrt{\frac{41}{2}}[/tex]

More can be learned about quadratic functions at https://brainly.com/question/24737967

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