[tex]\textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh ~~ \begin{cases} b=base\\ h=height\\[-0.5em] \hrulefill\\ h=6\\ A=48 \end{cases}\implies \begin{array}{llll} 48=\cfrac{1}{2}(b)(6)\implies 48=3b \\\\\\ \cfrac{48}{3}=b\implies 16=b \end{array}[/tex]
