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A physical therapy exercise has a person shaking a 5.00 kg weight up and down rapidly. if the barbell is moving at 4.50 m/s, what is the magnitude of the force required to stop it in 0.333 seconds?

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onyebuchinnaji

The magnitude of the force required to stop the weight in 0.333 seconds is 67.6 N.

Magnitude of required force to stop the weight

The magnitude of the force required to stop the weight in 0.333 seconds is calculated by applying Newton's second law of motion as shown below;

F = ma

F = m(v/t)

F = (mv)/t

F = (5 x 4.5)/0.333

F = 67.6 N

Thus, the magnitude of the force required to stop the weight in 0.333 seconds is 67.6 N.

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