Using the binomial distribution, it is found that there is a 0.1008 = 10.08% probability that exactly 18 of them say job applicants should follow up within two weeks.
The formula is:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
The values of the parameters are given as follows:
n = 25, p = 0.62.
The probability that exactly 18 of them say job applicants should follow up within two weeks is P(X = 18), hence:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 18) = C_{25,18}.(0.62)^{18}.(0.38)^{7} = 0.1008[/tex]
0.1008 = 10.08% probability that exactly 18 of them say job applicants should follow up within two weeks.
More can be learned about the binomial distribution at https://brainly.com/question/24863377
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