Respuesta :
0.811 M is the molar concentration of a 252.6 ml aqueous solution prepared with 70.3 g of sugar.
Define molarity of a solution.
Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution.
Given data:
252.6 mL = 0.2526 L
Next, we shall determine the number of moles of the sugar. This can be obtained as follow:
Molar mass of sugar = 342.30 g/mol.
Mass of sugar = 70.3 g
Mole of sugar =?
Mole =[tex]\frac{mass}{molar \;mass}[/tex]
Mole = [tex]\frac{70.3 g}{342.30}[/tex]
Mole of sugar = 0.205 mole
Finally, we shall determine the molar concentration of the sugar. This can be obtained as follow:
Mole of sugar = 0.205 mole
Volume = 0.2526 L
Molarity =?
Molarity = [tex]\frac{Moles \;solute}{Volume of solution in litre}[/tex]
Molarity = [tex]\frac{0.205 mole}{ 0.2526 L}[/tex]
Molarity = 0.811 M
Therefore, the molar concentration of the solution is 0.811 M
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