The definite integral of the given function will be [tex]\pi(\dfrac{1304}{27})[/tex].
Integration is defined as the summing up of the small parts to find the total value.The given function y = -x +2 will be integrated as follows:-
The limits are given as a = 0 and b = 2.
The integration will be done as:-
[tex]V = \pi\int_0^2\pi(y^2)dx\\\\\\V = \pi\int _0^2(\pi(-x+2)^2dx\\\\\\V = \pi\int _0^2(x^2+16+8x)dx\\\\\\V=\pi [ (\dfrac{x^3}{3}+16x+\dfrac{8x^2}{2}]_0^2\\\\\\V = \pi[(\dfrac{2^3}{3^3}+(16\times 2) + 8\dfrac{2)^2}{2}]-0\\\\\\V = \dfrac{1304}{27}\pi[/tex]
Therefore definite integral of the given function will be [tex]\pi(\dfrac{1304}{27})[/tex].
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