nimphabott nimphabott

13-06-2022
Mathematics

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make r the subject of the relation y = [tex]\frac{x-r}{x+r}[/tex]

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konrad509 konrad509

13-06-2022

[tex]y=\dfrac{x-r}{x+r}\\\\y(x+r)=x-r\\xy+ry=x-r\\ry+r=x-xy\\r(y+1)=x-xy\\r=\dfrac{x-xy}{y+1}[/tex]

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