The number of possible outcomes is 8.
The probability of getting exactly one tail is 3/8.
The probability of getting at most two tails is 3/4.
What are the probabilities?
Here is the sample space if 3 coins are tossed: {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}. There are 8 possible outcomes.
The probability of getting exactly one tail = number of times only one tail is gotten / total number of possible outcomes
3/8.
The probability of getting at most two tails = number of times at most two tails is gotten / total number of possible outcomes = 6/8 = 3/4
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