Respuesta :
The balanced chemical equation:
[tex]2 KNO_3 + H_2CO_3[/tex] → [tex]K_2CO_3 +2 HNO_3[/tex]
[tex]KNO_3[/tex] is the limiting reactant.
81.5% is the theoretical yield of potassium carbonate.
What is a balanced chemical equation?
A balanced equation contains the same number of each type of atom on both the left and right sides of the reaction arrow.
[tex]2 KNO_3 + H_2CO_3[/tex] → [tex]K_2CO_3 +2 HNO_3[/tex]
According to the equation, n ([tex]KNO_3[/tex]) = 2 x n ([tex]H_2CO_3[/tex]) = 2 x n ([tex]K_2CO_3[/tex])
n =[tex]\frac{m}{M}[/tex]
M ([tex]KNO_3[/tex]) = 101.1 g/mol
M ([tex]H_2CO_3[/tex]) = 62.03 g/mol
M ([tex]K_2CO_3[/tex]) = 138.2 g/mol
n ([tex]K_2CO_3[/tex]) = [tex]\frac{8.45}{138.2}[/tex] = 0.061 mol
n ([tex]KNO_3[/tex])available = [tex]\frac{15.15}{101.1}[/tex] = 0.15 mol
n ([tex]H_2CO_3[/tex]) = 0.228 mol
The required amount of n ([tex]KNO_3[/tex]) = 2 x n ([tex]H_2CO_3[/tex]) = 2 x 0.228 = 0.456 mol.
This is more than the available amount (0.15 mol).
That is why [tex]KNO_3[/tex] is the limiting reactant.
Due to this, the anticipated amount of [tex]K_2CO_3[/tex] is:
n ([tex]K_2CO_3[/tex]) = 1/2 x n ([tex]KNO_3[/tex]) = [tex]\frac{0.15 }{2}[/tex] = 0.075 mol
m ([tex]K_2CO_3[/tex]) = n x M = 0.075 x 138.2 = 10.365 g
% ([tex]K_2CO_3[/tex]) = [tex]\frac{8.45 X 100}{10.365}[/tex] = 81.5%
Learn more about the balanced chemical equation here:
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